<> Talking about C Data storage in language

The storage of a variable needs to open up new space in memory , Let's have a deep understanding today C Data storage in language .
C Data storage in language , It can be divided into four aspects :
1. Data type introduction
2. Shaping storage in memory : Original code , Inverse code , Complement
3. Introduction and judgment of byte order of big and small end
4. Analysis of floating point storage in memory

<> Data type introduction

The meaning of type : The size of memory space opened up with this type ( Size determines range )
Basic classification of types :
Plastic surgery Family , Floating point family , Tectonic type , Pointer type , Null type (void)

<> Shaping storage in memory

Next, we talk about how to store data in the memory
example :
int a=10;
int Is an integer variable , open up 4 A space of two bytes a.
When we want to explore how to store , Let's look at the original code first , Inverse and complement .
Original code , Inverse and complement
There are three expressions of signed number in computer , Original code , Inverse and complement .
There are sign bits and numeric bits in the three representations , Symbol bit “0” Show positive ,“1” It means negative .
Original code
Translate numbers directly into binary
Inverse code
Keep the sign bit of the original code unchanged , The other bits can be reversed in turn
Inverse code +1 Get the complement
The primitive of positive numbers , back , All complements are the same
In computer system , All numerical values are expressed and stored by complements . The reason is that , Use complement , The symbol bit and the numeric field can be unified ; with
Time , Addition and subtraction can also be dealt with in a unified way (CPU Only adders ) in addition , Mutual conversion between complement code and original code , The operation process is the same , No need Additional hardware circuits are required .

The number in memory is hexadecimal , So why isn't it shown 00 00 00 01 What about it ?
Here is another point of knowledge —— Big end / Small end storage
Introduction and judgment of byte order of big and small end
What is big / Small end storage ?
Big end storage : Save the low bit of data to the high address of memory , The high bit is stored in the low address
Small end storage : Store the high bit in the data to the high address in the memory , The low bit is stored in the low address
Notation : The big end is opposite , A short photo
How to judge the current machine size / Small end storage ?
int main() { int a=1; char* p=(char*)&a;//a Cast bit char*, Take one character if(*p==1) { printf(
" Small end \n"); } else { printf(" Big end "); } return 0; }
<> Analysis of floating point storage in memory

According to international standards , Any binary floating point number can be expressed in the following form :
(-1)^S * M * 2^E
(-1)^S Symbol bit ,s = 0 Be positive s = 1 It's negative
M Represents a significant number , greater than 1 less than 2
2^E Indicates the exponent
example : decimal system 5.0, Write in binary 101.0, amount to 1.01x2^2. Can exit S = 0, M = 1.01,E=2
IEEE 754 regulations : about 32 Bit floating point number , highest 1 Bit is sign bit S, Come down 8 Digit index E, The rest is 23 Significant number M.

Single precision floating point
IEEE745 Where is the significant number M And index E, There are some special requirements
Significant number M:1<=M<2
754 regulations , Save it inside the computer M Time , By default, the first digit of this number is always 1, So it can be discarded , Save only the following xxxxxx part . For example, preservation 1.01 When I was young , Save only 01, Wait until it's read , And the first one 1 Add it up . The purpose of doing so , It's saving 1 Three significant digits . with 32 Take the floating point number as an example , For M only 23 position , Will be the first 1 After giving up , It means it can be saved 24 Three significant digits
index E: The situation is quite special
first E Is an unsigned integer , If E yes 8 position Its value range 0 - 255; If E yes 11 position Its value range 0 -
2047. But we know that in scientific counting E Negative numbers are possible , therefore **IEEE754 regulations
: When stored in memory E The true value of must be added with an intermediate number , about 8 Positional E, The middle number is 127; about 11 Positional E, Intermediate number 1023.** for example :2^10 Of E yes 10, So save it as 32 Bit floating point number , Must be saved as 10+127=137, Namely 10001001
index E There are three situations when fetching from memory :
1,E Not all 0 Or not all 1

At this time , Floating point numbers are represented by the following rules , The index E Subtract the calculated value of 127( or 1023), Get the real value , Then add the significant number M First and foremost 1. such as :
0.5(1/2) The binary form of is 0.1, Because the positive part must be 1, That is to move the decimal point to the right 1 position , Then 1.0*2^(-1), Its order code is -1+127=126, Expressed as 01111110, And the mantissa 1.0 Remove the integer part to 0, Make up 0 reach 23 position 00000000000000000000000, The binary representation is 0
01111110 00000000000000000000000

2,E All for 0

At this time , Index of floating point numbers E be equal to 1-127( perhaps 1-1023) This is the true value ,
Significant number M No more first 1, Instead, it's reduced to 0.xxxxxx Decimals of . This is to show that ±0, And close to 0 It's a very small number

3,E All for 1

At this time , If significant number M All for 0, express ± Infinity ( The positive and negative depend on the sign bit s)

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