- 2020-08-18 07:03
*views 2*- bounding
- YOLO
- Paper reading notes
- box

One ,yolov1 bounding box

bounding box How did it happen ? Produced by regression , regression ? oh dear , Oh, my God , I have forgotten what it is to return , ok , Let me give you an example of linear regression in junior high school

There are two sets of data A and B

A = [1,2,3,4,5]

B = [2,4,6,8,10]

Using the thought of regression to predict when A by 6 When B What is the corresponding value

Obviously, the regression parameter is 2, The regression process is y = 2x, therefore A by 6 When B The corresponding value should be 12, This is the simplest way to go back .

then yolo1 It is mentioned that the whole image is directly used to generate the network structure 7*7 Of grid cell, each grid

cell forecast x,y,w,h,confidence And so on , among confidence namely IOU It's worth it . The key is this bounding

box How did it come about , To me this kind of small white is still entangled for several days, calculate to understand to lose , So make a quick note , Welcome everyone to correct （ Excuse me for thinking too much , At my level blog And the big guy [ Laugh and cry ]）

good , Let's have a look Annotation Inside XML file , Take a look at it

You can see the Bounding box Is the format of , All by [xmin,xmax,ymin,ymax] form , What about the central coordinates ?

review yolov1 The paper also said that the coordinates and the length and width should be normalized , You don't get your central coordinates back ? At the end of the day scipts eureka vol_label.py The file knows that the center coordinates are based on the label xmin,xmax,ymin,ymax Calculated , Ha ha ha , See the code note below .

def convert(size, box): dw = 1./size[0] # In normalization, the width is divided by the whole image_size Width of dh =

1./size[1] # Normalization is done by dividing the height by the whole image_size The height of x = (box[0] + box[1])/2.0 #

use (xmin+xmax)/2 obtain x The center point of y = (box[2] + box[3])/2.0 # use (ymin+ymax)/2 obtain y The center point of w =

box[1] - box[0] # Then the width is used xmax-xmin Calculated h = box[3] - box[2] #

Then the height is used ymax-ymin Calculated x = x*dw # Normalized central coordinates x w = w*dw # normalization bbox width y = y*dh #

Normalized central coordinates y h = h*dh # normalization bbox height return (x,y,w,h) def convert_annotation(year,

image_id): in_file = open('VOCdevkit/VOC%s/Annotations/%s.xml'%(year,

image_id)) out_file = open('VOCdevkit/VOC%s/labels/%s.txt'%(year, image_id),

'w') tree=ET.parse(in_file) root = tree.getroot() size = root.find('size') w =

int(size.find('width').text) h = int(size.find('height').text) for obj in

root.iter('object'): difficult = obj.find('difficult').text cls =

obj.find('name').text if cls not in classes or int(difficult) == 1: continue

cls_id = classes.index(cls) xmlbox = obj.find('bndbox') # Getting annotation bbox And returned in tuples

b = (float(xmlbox.find('xmin').text), float(xmlbox.find('xmax').text),

float(xmlbox.find('ymin').text), float(xmlbox.find('ymax').text)) #

towards convert afferent size = (w,h), and b, They are (xmin,xmax,ymin,ymax) bb = convert((w,h), b)

out_file.write(str(cls_id) + " " + " ".join([str(a) for a in bb]) + '\n')

We have the central coordinates x,y and bbox Of w,h In this way, regression parameters can be trained happily

Waiting for the shift .. ..

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